计算两个GPS坐标的距离
PHP计算两个GPS点之间的距离
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<pre class="inline:true class:language-php decode:1 " > #lng为经度，lat为纬度，一定不要弄错了哦 function distance($lat1, $lng1, $lat2, $lng2){ return (2*ATAN2(SQRT(SIN(($lat1-$lat2)*PI()/180/2) *SIN(($lat1-$lat2)*PI()/180/2)+ COS($lat2*PI()/180)*COS($lat1*PI()/180) *SIN(($lng1-$lng2)*PI()/180/2) *SIN(($lng1-$lng2)*PI()/180/2)), SQRT(1-SIN(($lat1-$lat2)*PI()/180/2) *SIN(($lat1-$lat2)*PI()/180/2) +COS($lat2*PI()/180)*COS($lat1*PI()/180) *SIN(($lng1-$lng2)*PI()/180/2) *SIN(($lng1-$lng2)*PI()/180/2))))*6378140; } |
调用方法：
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<pre class="inline:true class:language-php decode:1 " >echo distance(39.91917,116.3896,39.91726,116.3940); |
Mysql计算两GPS坐标的距离
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<pre class="inline:true class:language-sql decode:1 " >drop function getDistance; DELIMITER $$ CREATE DEFINER=<pre class="inline:true decode:1 " >root |
@[crayon-662bb1671c1297 …
